PHYS 252
Dr. Holmes
Introductory Remarks
Introduction to Quantum Theory
Quantum Theory
Atomic Physics
Boltzmann Distribution
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Classical theory accounts for the results of many, many experiments and almost all of the everyday experiences. But there are several experiments that classical theory cannot account for. In fact, classical theory predicts results contrary to experimental evidence in these cases. As a result, a new theory had to be developed. Actually, there are two regions where classical theory breaks down. One place is where the speeds of particles become an appreciable fraction of the speed of light. This area of breakdown led Einstein to his famous theory of relativity. The other place where classical theory breaks down is where the times and distances being considered become very small. This breakdown led to the quantum theory. In this part we consider the quantum theory. (In Part IV we consider relativity. In Part V we consider an area that requires both quantum and relativity: nuclear physics and radioactivity.)
The key to this and the next section is: a theory is only as good as the experiments it can account for and must be modified or abandoned in the face of experiments that contradict it.
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40) Qualitatively graph the power output per wavelength vs. wavelength curve for a blackbody.
41) The sun's power output per wavelength vs. wavelength curve peaks at a wavelength of 500 nm. (a) Assuming the sun is a perfect blackbody [a good but not perfect assumption], calculate its surface temperature. (b) What is the total power output of the sun? (RSUN = 6.96 x 105 km.) (c) What is the Power/Area at the Earth's distance from the sun?
42) Assume a person has a total body surface area of 1.9 square meters and an emissivity of 97%. (a) At what wavelength does the radiation output peak? (b) How much radiation is emitted? (c) How much does the person absorb if the air temperature is 24°C?
43) What did the classical theory predict for blackbody radiation?
44) What was the key to Planck's solution to the blackbody radiation problem?
45) (a) What is the photoelectric effect? (b) State two cases where the classical theory failed to predict the actual results. (c) Explain how the photon theory accounts for these results.
46) The work function for Aluminum is 4.08 eV. (a) What is the cut-off frequency? (b) What is the stopping voltage for light of wavelength 250 nm (in the UV) ?
47) Is Compton scattering explained by the wave theory, the particle theory, by both theories, or by neither theory?
48) (a) What is the approximate size of an atom? (b) of a nucleus? (c) of an electron? (d) How do we know this?
49) What is the weakness of classical theory in its attempt to describe atomic structures?
50) Describe Bohr's planetary model of the atom and give his two postulates.
51) (a) What is meant by the ground state of an atom? (b) Under what conditions is the energy of a planetary electron said to be zero?
52) (a) What is the ground state energy of the hydrogen atom? (b) How much energy does it take to ionize the hydrogen atom? (c) What would be the maximum wavelength of light that would be able to do this? (d) What kind of photon is this (i.e., ultraviolet, visible, IR, etc.) ? (e) How much energy would it take to excite a hydrogen atom in the ground state up to the n=3 state? (f) What would be the possible decay schemes for this excited state, and the energy, wavelength, and color of the photons emitted in each scheme?
53) What is the radius of the electron's orbit in (a) the ground state, and (b) the n=3 state of hydrogen?
ANSWERS TO SUPPLEMENTARY PROBLEMS:
41) a) 5800 K; b) 3.9 x 1026 Watts; c) 1400 W/m2 (standard value is 1350 W/m2)
42) assuming T of skin = 35°C = 95°F: a) 9.6 mm; b) 940.4 Watts; c) 813.1 Watts.
46) a) 9.85 x 1014 Hz; b) 0.89 Volts.
52) a) -13.6 eV; b) 13.6 eV; c) 91.4 nm; d) UV; e) 12.09 eV; f-1) 3 ® 1, E = 12.09 eV, l = 103 nm, UV; f-2) 3 ® 2 ® 1, E = 1.89 eV & 10.20 eV, l = 658 nm & 122 nm, red & UV.
53) a) 5.53x10-11 m; (b) 4.77x10-10 m.
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OUTLINE
SUPPLEMENTARY PROBLEMS (S- ):
54) a) If there is such a thing as the DeBroglie wavelength for matter, then we should be able to test it. Describe one experiment in support of the DeBroglie wavelength. b) Tell how the DeBroglie wavelength "explains" the Bohr assumption that L=nh.
55) List three experiments that support the wave nature of light. List three experiments that support the particle nature of light.
56) List one experiment that supports the particle nature of matter. List one experiment that supports the wave nature of matter.
57) (a) What is the minimum uncertainty in the position of an electron if it is moving at 300 m/sec with an uncertainty of 0.01% ? (b) What is the minimum uncertainty in the position of a bullet of mass 2 grams moving at the same speed with the same uncertainty in the speed?
58) Demonstrate the Heisenberg Uncertainty Principle by describing one experiment that tries to measure those quantities that it relates.
59) Write Schrodinger's equation. Where does it come from?
ANSWERS TO SUPPLEMENTARY PROBLEMS:
57) a) 4 mm; b) 2x10-30 m.
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SUPPLEMENTARY PROBLEMS (S- ):
60) Identify the four quantum numbers of the hydrogen atom and tell what each quantizes and the range of possible values each can take on.
61) State the Pauli Exclusion Principle and tell how it relates to the table of the elements.
62) Explain the principles of a laser. In particular, explain what is meant by (a) a metastable state, (b) a population inversion, (c) stimulated emission vs. spontaneous emission.
The Probability of one atom having n units of energy is based on equal likelyhood of any state. Below is a listing of all possible states for two cases:
CASE I: four atoms having three units of energy:
Below the four numbers refer to atoms A B C D having that number of units:
|
3 0 0 0 |
2 1 0 0 |
1 2 0 0 |
1 0 2 0 |
1 0 0 2 |
1 1 1 0 |
|
0 3 0 0 |
2 0 1 0 |
0 2 1 0 |
0 1 2 0 |
0 1 0 2 |
1 1 0 1 |
|
0 0 3 0 |
2 0 0 1 |
0 2 0 1 |
0 0 2 1 |
0 0 1 2 |
1 0 1 1 |
|
0 0 0 3 |
0 1 1 1 |
|
4 cases of one having 3 |
12 cases of one having 2 and one having 1 |
4 cases of three having one |
Total number of cases = 4 + 12 + 4 = 20.
Probability of atom A having n units is P(n):
P(3) = 1/20 = .05
P(2) = 3/20 = .15
P(1) = 6/20 = .30
P(0) = 10/20 = .50
CASE II: four atoms having five units of energy
Below the four numbers refer to atoms A B C D having that number of units:
|
5 0 0 0 |
4 1 0 0 |
1 4 0 0 |
1 0 4 0 |
1 0 0 4 |
1 1 1 2 |
|
0 5 0 0 |
4 0 1 0 |
0 4 1 0 |
0 1 4 0 |
0 1 0 4 |
1 1 2 1 |
|
0 0 5 0 |
4 0 0 1 |
0 4 0 1 |
0 0 4 1 |
0 0 1 4 |
1 2 1 1 |
|
0 0 0 5 |
2 1 1 1 |
4 ways of one having have 5; 12 ways of one having 4; 4 ways of none having none
|
3 2 0 0 |
2 3 0 0 |
2 0 3 0 |
2 0 0 3 |
3 1 1 0 |
1 3 1 0 |
1 1 3 0 |
1 1 0 3 |
|
3 0 2 0 |
0 3 2 0 |
0 2 3 0 |
0 2 0 3 |
3 1 0 1 |
1 3 0 1 |
1 0 3 1 |
1 0 1 3 |
|
3 0 0 2 |
0 0 3 2 |
0 0 3 2 |
0 0 2 3 |
3 0 1 1 |
0 3 1 1 |
0 1 3 1 |
0 1 1 3 |
12 ways of one having three and one having two; 12 ways of one having three and two having one
|
2 2 1 0 |
2 1 2 0 |
2 1 0 2 |
1 2 2 0 |
1 2 0 2 |
1 0 2 2 |
|
2 2 0 1 |
2 0 2 1 |
0 2 2 1 |
0 2 2 1 |
0 2 1 2 |
0 1 2 2 |
12 ways of two having two and one having one.
Total number of ways is 4+12+4+12+12+12 = 56
Probability of atom A having n units: P(n):
P(5) = 1/56 = .018
P(4) = 3/56 = .054
P(3) = 6/56 = .107
P(2) = 10/56 = .179
P(1) = 15/56 = .268
P(0) = 21/56 = .375

Notice the both curves look somewhat like dying exponentials.
Notice that has the energy goes up (from 3 to 5 units), the curves start lower but extend further out.
From this, it seems reasonable that the probability of any one atom having an energy E should be: P(E) = A exp(-aE) where A and a are determined by the total energy in the system.