We are given: B = 1 gauss = 1 x 10-4 T, North
I = 100 amps, East; L = 50 meters.
Fon current = I L B sin(qIB) =
(100 amps) (50 meters) (1 x 10-4 T) sin(90o) = 0.005 Nts directed up. (This is negligible compared to the weight of the cable!)
Letís now consider how this force will work on complete current circuits, not just individual lengths. Also, how can we make this magnetic force significant?